Minimum Load-Angular Contact Ball Bearings

In order to keep bearings working in a good condition, a minimum load must be imposed on bearings, particularly on bearings working at high speeds, high accelerations, or with the load direction changing frequently, because under these working conditions, inertial force of balls and cage and lubricant friction will have bad influence on the rotation of bearings, and detrimental sliding movement may be caused.

The minimum load of a single angular contact ball bearing can be obtained from

：

For the bearings arranged face-to-face or back-to-back

Where

Fmin ─ Minimum radial load, N

Famin ─ Minimum radial load, N

C0 - Static load rating,N

V ─ Oil viscosity at operating

temperature, mm2/s

n ─ Speed, r/min

dm ─ Mean diameter of bearing，dm=0.5(d+D)，mm

ka ─ Minimum axial load factor(see Table 1)

kr ─Minimum radial load factor(see Table 1)

Table 1

When bearings are started at low ambient temperatures or in the condition that the viscosity of lubricant is very high, a larger minimum load is need. Usually, the weight of bearing supporting parts plus the load on the bearing should be over the minimum load. If the weight can not be up to the minimum load, then extra radial load must be imposed on this type of bearing in order to meet the requirement of minimum load.

For single-row angular contact ball bearing and angular contact ball bearing arranged in tandem, the requirement can be met through adjusting the axial relative position of inner ring and outer ring, or preloading in axial with springs.

Basic load ratings in the product table are only suitable for mounting single bearing. Basic load ratings for single bearings arranged in pairs can be obtained from

Basic dynamic load ratings:

In tandem: C1=2C

Back to back or face to face or other arrangement: C1=1.62C

C-Basic dynamic load rating of a single angular contact ball bearing.

C1-Basic dynamic load rating of angular contact ball bearings arranged in tandem, face to face or back to bac

Basic rated static loading

C0 = 2 C0